Composition and Inverse
Composition and Inverse
Mat222
2/23/2013
This week we have been assigned three functions which we must evaluate. These are the functions which we have to evaluate this week. fx=2x+3 gx=x2-3 hx=7-x3
We have been asked to compute(f-h)(4).
So we can evaluate each separately and then subtract. f-h4=f4-h(4) f4=24+3
=8+3=11 f4=11 h4=7-43 =33=1 h4=1
This is our final answer. f-h4=11-1=10 Next we are to compare two pairs of the functions into each other. First we will work out. f°gx=f(gx) This means the rule of f will work on g.
=fx2-3 Here f is now going to work on the rule of g.
=2x2-3+5 The rule of f is applied to g.
=2x2-6+5 Simplifying f°gx=2x2-1 The final results.
Now we will compose the following: h°gx=h(gx) The rule of h will work on g. =hx2-3
=-7+(x2-3)3 The rule of h is applied to g. h°gx=-10+x23 The final results.
Next we are asked to transform g(x) so that the graph is placed 6 units to the right and 7 units downward for where it would be right now. * Six units to the right means to put a -6 in with x to be squared. * Seven units downward means to put -7 outside of the squaring. * The new functions will look like this: gx=(x-6)2-3-7 gx=(x-6)2-10
Our last job is to find the inverse of two of our functions, f and h. To find the inverse we will write the function with y instead of the function name, then we will switch the places of x and y, and solve for y again. Here are the functions: fx=2x+3 hx=7-x3
Here we replace f(x) and h(x) with y: y=2x+3 y=7-x3
Here we switch the y and the x: x=2y+3 x=7-y3
Now we solve for y: Subtract 3 from both sides. Multiply both sides by 3.
-3+x=2y 3x=7-y
One more
Mat222
2/23/2013
This week we have been assigned three functions which we must evaluate. These are the functions which we have to evaluate this week. fx=2x+3 gx=x2-3 hx=7-x3
We have been asked to compute(f-h)(4).
So we can evaluate each separately and then subtract. f-h4=f4-h(4) f4=24+3
=8+3=11 f4=11 h4=7-43 =33=1 h4=1
This is our final answer. f-h4=11-1=10 Next we are to compare two pairs of the functions into each other. First we will work out. f°gx=f(gx) This means the rule of f will work on g.
=fx2-3 Here f is now going to work on the rule of g.
=2x2-3+5 The rule of f is applied to g.
=2x2-6+5 Simplifying f°gx=2x2-1 The final results.
Now we will compose the following: h°gx=h(gx) The rule of h will work on g. =hx2-3
=-7+(x2-3)3 The rule of h is applied to g. h°gx=-10+x23 The final results.
Next we are asked to transform g(x) so that the graph is placed 6 units to the right and 7 units downward for where it would be right now. * Six units to the right means to put a -6 in with x to be squared. * Seven units downward means to put -7 outside of the squaring. * The new functions will look like this: gx=(x-6)2-3-7 gx=(x-6)2-10
Our last job is to find the inverse of two of our functions, f and h. To find the inverse we will write the function with y instead of the function name, then we will switch the places of x and y, and solve for y again. Here are the functions: fx=2x+3 hx=7-x3
Here we replace f(x) and h(x) with y: y=2x+3 y=7-x3
Here we switch the y and the x: x=2y+3 x=7-y3
Now we solve for y: Subtract 3 from both sides. Multiply both sides by 3.
-3+x=2y 3x=7-y
One more