Public Toilet
G answer B
F
A
1)
J
I
C
E
D
2) Cycle Time (CT) = Productive time per hour Output per day = 7 hrs./day X 60 min/hr X 60 sec/min 1008 units/day = 25,200 sec 1008 units = 25 sec/unit
6
5
4
3
2
1
3) Workstation =
J
I
G
H
F
E
C
D
B
A
Task Time 24 25 25 25 25 24 Idle Time = 1 0 0 0 0 1 ( Total = 2 sec )
4) WS = Sum of task times Cycle time (CT) = 148 sec 25 sec/units = 5.92 ˜ 6 units of WS
5) Efficiency = Sum of task times X 100% CT * Actual # of (WS) = 148 sec * 100 % ( 25 sec/units * 4 units of WS) = 98.67 %
6) Idle time per units = (CT * actual # of WS) – sum of task times = (25 sec/unit X 6 units of WS) – 148 seconds =
F
A
1)
J
I
C
E
D
2) Cycle Time (CT) = Productive time per hour Output per day = 7 hrs./day X 60 min/hr X 60 sec/min 1008 units/day = 25,200 sec 1008 units = 25 sec/unit
6
5
4
3
2
1
3) Workstation =
J
I
G
H
F
E
C
D
B
A
Task Time 24 25 25 25 25 24 Idle Time = 1 0 0 0 0 1 ( Total = 2 sec )
4) WS = Sum of task times Cycle time (CT) = 148 sec 25 sec/units = 5.92 ˜ 6 units of WS
5) Efficiency = Sum of task times X 100% CT * Actual # of (WS) = 148 sec * 100 % ( 25 sec/units * 4 units of WS) = 98.67 %
6) Idle time per units = (CT * actual # of WS) – sum of task times = (25 sec/unit X 6 units of WS) – 148 seconds =